3x^2-3=(-1/x^2)

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Solution for 3x^2-3=(-1/x^2) equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x^2-3 = -1/(x^2) // + -1/(x^2)

3*x^2-(-1/(x^2))-3 = 0

3*x^2+x^-2-3 = 0

t_1 = x^2

3*t_1^1+1*t_1^-1-3 = 0

3*t_1^1+1*t_1^-1-3*t_1^0 = 0

(3*t_1^2-3*t_1^1+1*t_1^0)/(t_1^1) = 0 // * t_1^2

t_1^1*(3*t_1^2-3*t_1^1+1*t_1^0) = 0

t_1^1

3*t_1^2-3*t_1+1 = 0

3*t_1^2-3*t_1+1 = 0

DELTA = (-3)^2-(1*3*4)

DELTA = -3

DELTA < 0

t_1 in { } 

x belongs to the empty set

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